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3a + e 31. c(12a) 22. ac + d 32. c2e + a 23. 4cd 33. d 2 + 7b 24. bd – 3e 34. 5(a + b)2 25. a 3 + ce 35. 6ce + 4a – d 26. 5ab – d 36. 5a 4 27. –ab + 10 37. ba3 + d2 28. 4b – 5e 38. (e + d)(e – d) 29. 3e 2+ 4b 39. 9(a + d ) – 92 30. 3(a + b + d) 40. 6(d + 3b) + 7ace 25 Team-LRN 2b + a 2(4) + 2 8+2 = 10 a 2 + 2b + c (2)2 + 2(3) + 7 4 + 2(3) + 7 4+6+7 = 17 – WORKING WITH ALGEBRAIC EXPRESSIONS – Skill Building until Next Time The next time you go shopping, take note of the price on any two items. Use a variable to represent the cost of the first item and a different variable to represent the cost of the second item.

When Kim works 40 hours in a week, she earns $560. If she only works 35 hours, how much should she expect to earn? 44. There are 40 questions on a test. How many questions do you need to have correct to score a 90% on the test? 45. Suppose you scored 80% on a test and answered 32 questions correctly. How many questions were on the test? 36 Team-LRN – SOLVING BASIC EQUATIONS – 46. Susan and Jayne have part-time jobs selling tickets at the theatre. This week, Jayne’s paycheck was twice the amount of Susan’s paycheck.

For example, 5 + 0 = 5. Let’s look at another equation: x – 5 = 9. What do you need to do to get the variable on a side by itself? You need to get rid of the 5. The equation says to subtract 5, so what undoes subtraction? If you said addition, you are right! In this problem, you need to add 5 to both sides of the equation to get rid of the 5. Example: x – 5 = 9 Add 5 to both sides of the equation. Simplify both sides of the equation. Add 0 to x. x–5+5=9+5 x + 0 = 14 x = 14 Example: a + 6 = 7 Subtract 6 from both sides of the equation.