Home Programming • Absolute Beginner's Guide to C (2nd Edition) by Greg Perry

Absolute Beginner's Guide to C (2nd Edition) by Greg Perry

By Greg Perry

For starting programmers, this up-to-date version solutions all C programming questions. This bestseller talks to readers at their point, explaining each element of ways to start and examine the c program languageperiod quick. Readers additionally discover the place to profit extra approximately C. This booklet comprises tear-out reference card of C services and statements, a hierarchy chart, and different beneficial info. It makes use of specified icons, notes, clues, warnings, and rewards to make figuring out more straightforward. And the transparent and pleasant sort presumes no programming wisdom.

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Extra info for Absolute Beginner's Guide to C (2nd Edition)

Sample text

Typically, what it tells you is exactly what you’d Item 2 | 23 predict. Occasionally however, it provides results that leave you scratching your head and turning to reference works or online Q&A sites for revelation. We’ll begin with the typical cases—the ones harboring no surprises. In contrast to what happens during type deduction for templates and auto (see Items 1 and 2), decltype typically parrots back the exact type of the name or expression you give it: const int i = 0; // decltype(i) is const int bool f(const Widget& w); // decltype(w) is const Widget& // decltype(f) is bool(const Widget&) struct Point { int x, y; }; // decltype(Point::x) is int // decltype(Point::y) is int Widget w; // decltype(w) is Widget if (f(w)) … // decltype(f(w)) is bool template // simplified version of std::vector class vector { public: … T& operator[](std::size_t index); … }; vector v; … if (v[0] == 0) … // decltype(v) is vector // decltype(v[0]) is int& See?

Auto x1 = 27; // type is int, value is 27 auto x2(27); // ditto auto x3 = { 27 }; // type is std::initializer_list, // value is { 27 } auto x4{ 27 }; // ditto This is due to a special type deduction rule for auto. When the initializer for an auto-declared variable is enclosed in braces, the deduced type is a std::initial izer_list. 0 }; // error! can't deduce T for // std::initializer_list Item 2 | 21 As the comment indicates, type deduction will fail in this case, but it’s important to recognize that there are actually two kinds of type deduction taking place.

First, it’s the only situation in template type deduction where T is deduced to be a reference. Second, although ParamType is declared using the syntax for an rvalue reference, its deduced type is an lvalue reference. , Case 1) rules apply. For example: template void f(T&& param); // param is now a universal reference int x = 27; const int cx = x; const int& rx = x; // as before // as before // as before f(x); // x is lvalue, so T is int&, // param's type is also int& f(cx); // cx is lvalue, so T is const int&, // param's type is also const int& f(rx); // rx is lvalue, so T is const int&, // param's type is also const int& f(27); // 27 is rvalue, so T is int, // param's type is therefore int&& Item 1 | 13 Item 24 explains exactly why these examples play out the way they do.

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